2[t-(2t+18)+15]=2(t+3)

Solution for 2[t-(2t+18)+15]=2(t+3) equation:

Simplifying
2[t + -1(2t + 18) + 15] = 2(t + 3)

Reorder the terms:
2[t + -1(18 + 2t) + 15] = 2(t + 3)
2[t + (18 * -1 + 2t * -1) + 15] = 2(t + 3)
2[t + (-18 + -2t) + 15] = 2(t + 3)

Reorder the terms:
2[-18 + 15 + t + -2t] = 2(t + 3)

Combine like terms: -18 + 15 = -3
2[-3 + t + -2t] = 2(t + 3)

Combine like terms: t + -2t = -1t
2[-3 + -1t] = 2(t + 3)
[-3 * 2 + -1t * 2] = 2(t + 3)
[-6 + -2t] = 2(t + 3)

Reorder the terms:
-6 + -2t = 2(3 + t)
-6 + -2t = (3 * 2 + t * 2)
-6 + -2t = (6 + 2t)

Solving
-6 + -2t = 6 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.
-6 + -2t + -2t = 6 + 2t + -2t

Combine like terms: -2t + -2t = -4t
-6 + -4t = 6 + 2t + -2t

Combine like terms: 2t + -2t = 0
-6 + -4t = 6 + 0
-6 + -4t = 6

Add '6' to each side of the equation.
-6 + 6 + -4t = 6 + 6

Combine like terms: -6 + 6 = 0
0 + -4t = 6 + 6
-4t = 6 + 6

Combine like terms: 6 + 6 = 12
-4t = 12

Divide each side by '-4'.
t = -3

Simplifying
t = -3